Today in Tribe History: November 30, 1948

Indians shortstop and manager Lou Boudreau is named the American League’s Most Valuable Player. He becomes just the second Cleveland player to earn the honor (George Burns, 1926).

Boudreau took home 22 of the 24 first place votes for the award after the best year of his then eleven-year MLB career. He had finished third in the voting in 1947.

Boudreau finished the 1948 season with a .355 batting average (second to Boston’s Ted Williams), 18 home runs, and 106 runs batted in, all career highs. In 676 plate appearances in 152 games that season, he struck out just nine times while walking 98. His efforts on the field and in the dugout helped to lead Cleveland to their first championship since 1920.

Only one Indians player has earned the honor since Boudreau – Al Rosen in 1953.

Related Posts

Today in Tribe History: June 25, 2011

In one of the more unfortunate and unusual losses of the season, the Indians fell to the San Francisco Giants, 1-0, as the lone run of the…

Today in Tribe History: June 24, 1997

Less than three years after signing with the club, 21-year-old right-hander Jaret Wright makes his Major League debut in front of a packed Jacobs Field crowd and…

Today in Tribe History: June 23, 1968

For the sixth time this season, Luis Tiant throws a complete game shutout as he and his Cleveland teammates blank the Detroit Tigers, 3-0.

Today in Tribe History: June 22, 2001

The Cleveland Indians acquire the highly controversial John Rocker from the Atlanta Braves with a minor leaguer for relievers Steve Karsay and Steve Reed.

Today in Tribe History: June 21, 1956

The “Red Baron”, Rick Sutcliffe, is born in Independence, Missouri.

Today in Tribe History: June 20, 1951

Cleveland gets an impressive day at the plate from second baseman Bobby Avila as the Indians knock off the Boston Red Sox, 14-8.

Leave a Reply

Your email address will not be published.